It is launched upward at 55掳 above the horizontal plane. How fast is it moving at the top of its curve?

Suppose a projectile is launched upward at 55掳 above the horizontal plane. How fast is it moving at the top of its curved trajectory?It is launched upward at 55掳 above the horizontal plane. How fast is it moving at the top of its curve?You need to provide the velocity at which it was projected.



However, if we assume that velocity to be v, then the velocity at the top of its trajectory will be:



v cos (55)



Explanation: The velocity v can be broken down into two components,

v cos (55) - Horizontal component

v sin (55) - Vertical component



At the top if its trajectory, the vertical component will become zero, as it wouldn't be moving up or down. After that point it becomes negative. The horizontal component remains the same throughout the projectile motion.It is launched upward at 55掳 above the horizontal plane. How fast is it moving at the top of its curve?you need to give more information if you want an answer. im sure someone can give you a formula for acceleration of an object of x weight, with x velocity, even wind resistance etc etc etc. i think what you are wanting involves differential calculus.

peterbilt