How do you calculate force required to move a car on an inclined plane?

F=ma is on a flat plane. What if there is an incline of say 5 degrees? Would it be F=maSin5?



Suppose the car to be 100kgs and the acceleration is 20km/hr.How do you calculate force required to move a car on an inclined plane?it would be the net force,,, rather



F-Wsin(5)=ma...or, F=Wsin(5) if it moving at constant velocity

where W is the weight of the car....





assuming no friction here by the way...How do you calculate force required to move a car on an inclined plane?if it's the angle of elevation, cosine.

oh wait, i forgot. i cant do this without paper.

total force is (100sin5)(9.8) + (100)(20sin5)



oh what the heck... that was several years ago.How do you calculate force required to move a car on an inclined plane?I think it is actually F=maCos 5 because if you think about it you cannot just input sin if there is an angle therefore sin would have to be in the original equation also. but sin of 0 is 0 so on a flat plane the force would be zero which isn't true therefore it must be cos because cos 0 is 1.